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A star behaves like a perfectly black body emitting radiant energy The ratio of radiant energy per second by this star to that emitted by another star having 8 times the radius of former, but having temperature, one-fourth that of the former in Kelvin is .A. `1:4`B. `1:16`C. `4:1`D. `16:1` |
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Answer» Correct Answer - C `P =sigma AT^(4) rArr P =sigma4 pi R^(2)T^(4)` `:.(P_(1))/(P_(2))=((R_(1))/(R_(2)))^(2)((T_(1))/(T_(2)))^(4)` . |
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