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A star emiting light of wavelength 4500Å is moving towards the eart with a speed of 3600 km/sec. Determine the wavelength shift and apparent wavelength due to Doppler effect. The speed of light is 3xx10^(8)m//s |
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Answer» SOLUTION :DATA supplied `v=3.6xx10^(6)m//s, "" lamda=4500xx10^(-10)m""c=3xx10^(8)m//s` `DELTA lamda=(v lamda)/c` and `Delta lamda=-lamda-lamda.` or `lamda.-lamda` `:.Delta lamda=(3.6xx10^(6)xx4500xx10^(-10))/(3xx10^(8))=54.00xx10^(-10)m=54Å` The apparent WAVELENGTH `lamda.= Delta -Delta lamda=4446Å` |
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