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(a) State Ampère's circuital law expressing it in the integral form. (b) Two long coaxial insulated solenoids S_(1) " and " S_(2) of equal lengths are wound one over the other as shown in the figure. A steady current 'I'flows through the inner solenoid S_(1) , to the other end B which is connected to the outer solenoid S_(2) , through which the same current 'I'flows in the opposite direction so as to come out at end A. If n_(1)" , and " n_(2)are the number of turns per unit length, find the magnitude and direction of the net magnetic field at a point (i) inside on the axis and (ii) outside the combined system. |
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Answer» Solution :(b) (i) The magnetic FIELD DUE to solenoid `S_(1)` , is inupward direction and due to solenoid `S_(2)` , the magnetic field is in downward direction. `n_(1) =` NUMBER of turns in solenoid `S_(1)` `n_(2)` = number of turns in solenoid `S_(2)` `B_(1) = mu_(0) n_(1) I` `B_(2) = mu_(0)n_(2)I` Net magnetic field `B = B_(1)- B_(2)` ` = mu_(0) n_(1) I - mu_(0) n_(2)I` ` = mu_(0)I (n_(1) - n_(2))` in upward direction (ii) Magnetic field will be ZERO outside the system |
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