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a. State the law of distances . b.Using the law deduce that an object between F and 2F a concave mirror produces real image beyond 2F. |
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Answer» Solution :a. `(1)/(V) + (1)/(u) = (1)/(f)` u - Object distance v - image distance f - FOCAL LENGTH b.For concave mirror, f `lt ` 0 Fro object, u `lt ` 0 For 2f `lt u lt f, ` we get `(1)/(2f) lt (1)/(u) lt (1)/(f) "" i.e.,- (1)/(2f)lt - (1)/(u) lt - (1)/(f) ` `(1)/(f) - (1)/(2f) lt (1)/(f) - (1)/(u) lt (1)/(f) - (1)/(f) ` `(2- f)/(2f) lt (1)/(v) lt 0 "" [ "SINCE" (1)/(v) = (1)/(f) - (1)/(u) ]` i.e,`(1)/(2f) lt (1)/(v) lt 0 `i.e., image lies on the left, beyond 2F and it is real. |
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