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A stationary observer receives a sound from a source of frequency 2000Hz moving with constant velocity. The apparent frequency varies with as shown in the figure The value of f_(m) is (2300-10x)Hz. Find the value of x. (Take speed of sound =30m//s and neglect the time taken by sound to reach the stationary observer). |
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Answer» Solution :`t_(m)=(V)/((v-v_(s)costheta)_("min"))xxf` `1800=(v)/((v+v_(s)costheta)_("min"))xxf` On SOLVING `f_(m)=2250 HZ` `=2300-50` |
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