1.

A stationary observer receives a sound from a source of frequency 2000Hz moving with constant velocity. The apparent frequency varies with as shown in the figure The value of f_(m) is (2300-10x)Hz. Find the value of x. (Take speed of sound =30m//s and neglect the time taken by sound to reach the stationary observer).

Answer»

Solution :`t_(m)=(V)/((v-v_(s)costheta)_("min"))xxf`
`1800=(v)/((v+v_(s)costheta)_("min"))xxf`
On SOLVING
`f_(m)=2250 HZ`
`=2300-50`


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