A stationary partical explodes into two partical of a masses `m_(1) and m_(2)` which move in opposite direction with velocities `v_(1) and v_(2)`. The ratio of their kinetic energies `E_(1)//E_(2)` isA. `m_2//m_1`B. `m_1//m_2`C. 1D. `m_1v_2//m_2v_1`

A stationary partical explodes into two partical of a masses `m_(1) an

1.	A stationary partical explodes into two partical of a masses `m_(1) and m_(2)` which move in opposite direction with velocities `v_(1) and v_(2)`. The ratio of their kinetic energies `E_(1)//E_(2)` isA. `m_2//m_1`B. `m_1//m_2`C. 1D. `m_1v_2//m_2v_1`
Answer» Correct Answer - A `m_1v_1=m_2v_2(P_1=P_2)` `E_1/E_2=(1/2m_1v_1^2)/(1/2m_2V_2^2)=((P_1^2)/(2m_1))/((P_2^2)/(2m_2))=m_2/m_1`

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A stationary partical explodes into two partical of a masses `m_(1) and m_(2)` which move in opposite direction with velocities `v_(1) and v_(2)`. The ratio of their kinetic energies `E_(1)//E_(2)` isA. `m_2//m_1`B. `m_1//m_2`C. 1D. `m_1v_2//m_2v_1`

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