1.

A stationary sound wave has frequency 165 Hz (speed of sound in air = 330 m/s), then distance between two consecutive nodes is :

Answer»

2 m
0.5 m
1 m
4 m

Solution :WAVELENGTH `lambda = (U)/(v) = (330)/(165)= 2m`
distance between two consecutive nodes = `(lambda)/(2) ` = 1m
THUS correct choice is (C).


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