A stationary wave on a stretched string has an equation given by y = 10 sin (2pi x)/(3) cos 8 pit, where x and y are in cm and t is in second. Then separation between the two adjacent nodes is given by :

A stationary wave on a stretched string has an equation given by y = 1

1.	A stationary wave on a stretched string has an equation given by y = 10 sin (2pi x)/(3) cos 8 pit, where x and y are in cm and t is in second. Then separation between the two adjacent nodes is given by :
Answer» 1.5 cm 3 cm `(1)/(3) `cm `(1)/(6) ` cm Solution :The general equation of stationary wave is y = a sin kx cos `omega`t y= 10 sin `(2pi x)/(3) ` cos 8`pi` t sok = `(2pi)/(3) and omega = 8 pi `. `(2pi)/(lambda) = (2pi)/(3)rArr lambda = 3` cm. So DISTANCE between two CONSECUTIVE NODES ` = (lambda)/(2) = 1.5` cm . correct CHOICE is a.

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A stationary wave on a stretched string has an equation given by y = 10 sin (2pi x)/(3) cos 8 pit, where x and y are in cm and t is in second. Then separation between the two adjacent nodes is given by :

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