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A steady current of 2 amperes was passed through two electrolytic cells X and Y connected in series containing electrolytes FeSO_(4) and ZnSO_(4) until 2.8 g of Fe deposited at the cathode of cell X. How long did the current flow?Calculate the mass of Zn deposited at the cathode of cell Y. (Molar mass : Fe=56 g"mol"^(-1)Zn=65.3"g mol"^(-1), F=96500"C mol"^(-1)) |
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Answer» SOLUTION :`m=z I t` `2.8g=(56xx2xx t)/(2xx96500)` `t=4825s` `(m_(1))/(m_(2))=(E_(1))/(E_(2))` `(2.8)/(MZN)=(56)/(2)xx(2)/(65.3)` `mZn=3.265g` |
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