1.

A steady current of 2 amperes was passed through two electrolytic cells X and Y connected in series containing electrolytes FeSO_(4) and ZnSO_(4) until 2.8 g of Fe deposited at the cathode of cell X. How long did the current flow?Calculate the mass of Zn deposited at the cathode of cell Y. (Molar mass : Fe=56 g"mol"^(-1)Zn=65.3"g mol"^(-1), F=96500"C mol"^(-1))

Answer»

SOLUTION :`m=z I t`
`2.8g=(56xx2xx t)/(2xx96500)`
`t=4825s`
`(m_(1))/(m_(2))=(E_(1))/(E_(2))`
`(2.8)/(MZN)=(56)/(2)xx(2)/(65.3)`
`mZn=3.265g`


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