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A steam engin intakes 100g of steam at `100^((0))C` per minute and cools it down to `20^((0))C`. Calculate the heat rejected by the steam engine per minute. Latent heart of vaporization of steam `=540 cal g^(-1)`. |
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Answer» Heat rejected during the condensation of steam in one minute `=(100 g)xx(540 cal g^(-1)=5.4xx10^(-4) cal`. Heat rejected during the cooling of water `=(100 g)xx(1 cal g^(-1)(0)C^(-1))(100(0)C-20(0)C)` `=8000 cal`. Thus, heat rejected by the engine per minute `=5.4xx10^(4) cal+0.8xx10^(4) cal` `=6.2xx10^(4)cal`. |
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