1.

A steel ball of density 8.0 xx 10^(3) kg//m^(3)and radius 2 mm is observed to fall with a terminal velocity 1.0 xx 10^(-2) m//sin a liquid of density 1.8 xx 10^(3) kg//m^(3) . Calculate the viscosity of the liquid.

Answer»

SOLUTION :We have,
`ETA = (2R^(2)(d-d_(0))g)/(9u)`
`=(2(2 xx 10^(-3))^(2) (8.0 xx 10^(3) - 1.8 xx 10^(3)) xx 9.8)/(9 xx 1.0 xx 10^(-2))`
`=5.4 Nm^(-2) s`


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