Saved Bookmarks
| 1. |
A steel ball of mass m_(1)=1kg moving with velocity 50ms^(-1) collides with another ball of mass m_(2)=200g lying on the ground. Due the collision, the KE is lost and their internal energies change equally and T_(1) and T_(2) are the temperature changes of masses m_(1) and m_(2) respectively. If the specific heat of steel is unity and J="4.18 J cal"^(-1), then |
|
Answer» `T_(1)=7.1^(@)C and T_(2)=1.47^(@)C` |
|