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A steel drill is making 180 revolution per minute, under a constant forque of 5N-m. If it drills a hole in 7sec in a steel block of mass 600gm, rise in temperature of the block is `(S=0.1 gm^(-1).^(@)C^(-1))`A. `2.6^(@)C`B. `1.3^(@)C`C. `5.2^(@)C`D. `3^(@)C` |
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Answer» Correct Answer - A `tau omegat=JmSDeltatheta(omega=2pin)` |
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