1.

A steel rod 2.0 m long has a cross-sectional area of `0.30cm^(2)`. The rod is now hung by one end from a support structure, and a 550 kg milling machine is hung from the strain, and the elongation of the rod.

Answer» `"Stress"=(F_(_|_))/(A)=((500kg)(9.8m//s^(2)))/(3.0xx10^(-5)m^(2))`
`=1.8xx10^(8)Pa`
`"Strain "=(Deltal)/(l_(0))=("Stress")/(Y)=(1.8xx10^(8)Pa)/(20xx10^(10)Pa)`
`=9.0xx10^(-4)`
Elongation = `Deltal`
`="(strain)"xxI_(0)`
`=(9.0xx10^(-4))(2.0m)`
`=1.8 mm`


Discussion

No Comment Found

Related InterviewSolutions