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A steel rod of diamerer 1 am is clamped firmly at each end when its temperature is `25^(@)C` so that it cannot contract on cooling The tension in the rod at `0^(@)C` is approximately `(alpha=10^(-5)//^(@)C,Y=2xx10^(11)Nm^(-2))`A. 4000 NB. 7000 NC. 7400 ND. 4700 N |
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Answer» Correct Answer - A Strain `=(Deltal)/l=alphaDelta theta` Strss = Y xx strain = Y `alpha Delta theta` `therefore` Force or tension, T = stress xx are = YA `alpha Delta theta` `" " =(piYalphad^(2)Deltatheta)/4(A=(pid^(2))/4)` or `" " T=(pi xx 2 xx 10^(11) xx 10^(-5) xx 10^(-4) xx25)/(=3926N~~400N)` |
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