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A steel wire can support a maximum load of W before reaching its elastic limit. How much load can another wire, made out of identical steel, but with a radius one half the radius of the first wire, support before reaching its elastic limit?A. WB. `(W)/(4)`C. `(W)/(4)`D. `4W`

Answer» Correct Answer - C
Breaking force = Breaking stress `xx` Area of cross section .
for given material of the wire, breaking stree is constant .
`therefore (F_(1))/(A_(1)) =(F_(2))/(A_(2))`
`F_(2) = F_(1) ((A_(2))/(A_(1))) = F_(1)((A_(1)//4)/(A_(1))) = (F_(1))/(4) = (W)/(4)" "(because r_(2) = r_(1//2))`


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