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A steel wire length 20cm and uniform cross sectional area of 1mm2 is tired rigidly at both the ends at 45^@. What will be the change in tension of the wire if the temperature of the wire is decreased to 20^@c . [Y forsteel = 2 xx 10^11 N/m^2. the coefficient of linear expansion for steel= 1.1 xx 10^-5 /(0c)] |
| Answer» SOLUTION :Coefficient of linear expansion`alpha = (Delta)/(L(DeltaT))` There for`(Delta)/(L) = alpha DeltaT-(i)` and `Y = (F. L)/(A Delta L)` (ii) there for F = Y A (Delta L)/(l) = YA alpha Delta T` from (i) F 2 xx 10^11 xx 1 xx 10^-6 xx 1.1 xx 10^-5 xx 25` = 55N. | |