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A step up transformer operates on a 230 V line and a load current of 2 ampere. The ratio of the primary and secondary windings is 1:25. What is the current in the primary ? |
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Answer» Solution :USING the relation `(N_(P))/(N_(S)) = (I_(S))/(I_(P)), I_(P) = (N_(S)I_(S))/(N_(P))` Here `N_(P)//N_(S) = 1//25` or `N_(S)//N_(P) = 25//1 = 25` and `I_(S) = 2A` Current in primary, `I_(P) = 25 xx 2 = 50 A` |
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