InterviewSolution
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InterviewSolution
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A stone at the end of `1m` long string is whirled in a vertical circle at a constant speed of `4ms^-1`. The tension in the string is `6N` when the stone isA. (a) `10ms^-1`B. (b) `5sqrt3ms^-1`C. (c) `10sqrt3ms^-1`D. (d) `20ms^-1` |
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Answer» Correct Answer - A `m=1kgimpliesL=10/3m` `(T_(max))/(T_(min))=4` (i) and `V_L=sqrt(V_H^2+4gL)` Tension at highest point, `T_(min)=(mv_H^2)/(K)-mg` Tension at lowest point, `T_(max)=mv_L^2//L+mg=(m(v_H^2+4gL))/(L)+mg` Now Eq. (i) can be written as `m[(v_H^2+4gL)/(L)+g]=4xxm((v_H^2)/(L)-g)` `implies v_H=sqrt(3gL)=10ms^-1` |
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