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InterviewSolution
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A stone drops from the edge of the roof. It passes a window 2 m high in `0*1 s`. How far is the roof above the top of the window? |
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Answer» Correct Answer - `19.4 m` Let h be the height of the roof above the top of the window and t be the time taken by the stone to reach the top of the window. `u=0,a=9.8m//s^(2)` from `h=ut+(1)/(2)g t^(2), h=0+(1)/(2)xx9.8(t+0.1)^(2)=4.9(t^(2)+0.01+0.2t)` and `h+2=0+(1)/(2)xx9.8(t+0.1)^(2)=4.9(t^(2)+0.01+0.2t)` using eqn. `4.9t^(2)=4.9t^(2)+4.9xx0.01=1.951` or `0.98t=2-4.9x0.01=1.951` or `t=1.951/0.98=1.999s` As `h=4.9t^(2), h=4.9(1.99)^(2)=19.4m`. |
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