1.

A stone is dropped into a well and sound of impact of stone with water is heard after 2.056 second of the release of stone from top If g980 cm/s^(2) and velocity of sound is 350 m/s. Then depth of well is :

Answer»

19.6 m
9.8 m
30 m
7 m

Solution :t = `t_(1) + t_(2)` .
`t = sqrt((2h)/(g)) + (H)/(V)` .
` t = sqrt((2 xx 29.6)/(9.8)) + (19.6)/(350)= 2 + 0.056= 2.056`SEC
Hence the correct CHOICE is (a ).


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