1.

A stone is projected with speed u and angle of projection is `theta`. Find radius of curvature at t=0.A. `(u^(2) cos^(2) theta)/g`B. `(u^(2))/(g sin theta)`C. `(u^(2))/(g cos theta)`D. `(u^(2) sin^(2) theta)/g`

Answer» Correct Answer - C
At t=0
`a_(bot)=g cos theta`,
`R=(v^(2))/(a_(bot))=(u^(2))/(g cos theta)`


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