InterviewSolution
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A stone is projected with speed u and angle of projection is `theta`. Find radius of curvature at t=0.A. `(u^(2) cos^(2) theta)/g`B. `(u^(2))/(g sin theta)`C. `(u^(2))/(g cos theta)`D. `(u^(2) sin^(2) theta)/g` |
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Answer» Correct Answer - C At t=0 `a_(bot)=g cos theta`, `R=(v^(2))/(a_(bot))=(u^(2))/(g cos theta)` |
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