InterviewSolution
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InterviewSolution
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A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground. |
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Answer» h = 19.6 m. Initial velocity u = 0 (∵ It starts from rest) From equation of motion. v2 = u2 + 2gh v2 = 0 + 2 x 9.8 x 19.6 = 19.6 x 19.6 ∴ v = \(\sqrt{19.6\times 19.6}\) = 19.6 ms-1 Final velocity of stone before touching the ground = 19.6 ms-1. |
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