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A stone is rotated in a vertical circle. Speed at bottommost point is `sqrt(8gR)`, where R is the radius of circle. The ratio of tension at the top and the bottom isA. `1:2`B. `1:3`C. `2:3`D. `1:4` |
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Answer» Correct Answer - B `T=(m u^(2))/(R)+"mg cos"theta,v^(2)=u^(2)-2gh` `T_("top")=3mg" and "T_("bottom")=9mg` Therefore, the ratio `(T_("top"))/(T_("bottom"))=(3mg)/(9mg)=(1)/(3)` |
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