A stone is thrown in a vertically upward direction with a velocity of 6 m/s. If the acceleration of the stone during its motion is 10 m/s2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

A stone is thrown in a vertically upward direction with a velocity of

1.	A stone is thrown in a vertically upward direction with a velocity of 6 m/s. If the acceleration of the stone during its motion is 10 m/s2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?
Answer» -STEP explanation:Given, initial velocity, u=5ms −1 Final velocity, v=0Since, u is UPWARD & a is downward, it is a retarded motion. ∴a=−10ms −2 HEIGHT attained by stone, s=?TIME take to attain height, t=?(i) Using the relation, v 2 −u 2 =2as, we haves=v 2 −u 2 /2a=(0) 2 −(5) 2 /2×(−10)=1.25m(ii) Using the relation, v=u+at0=5+(−10)t ort=5/10=0.5s

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A stone is thrown in a vertically upward direction with a velocity of 6 m/s. If the acceleration of the stone during its motion is 10 m/s2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?​

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A stone is thrown in a vertically upward direction with a velocity of 6 m/s. If the acceleration of the stone during its motion is 10 m/s2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?