1.

A stone is thrown vertically upward with a height 80 m with what speed it thrown​

Answer»

u =28 m/sa) When MAXIMUM height reached, velocity =0conserving total energy,21m×282=21m×D2+mgh→h=2×0.8282=40 mb) One second after u reaches maximum height t=1 SEC.V=u+at=0+9.8×1=9.8 m/sc) No, because at maximum height, velocity is zero so 1 sec after in any CASE, will given velocity 9.8×1=9.8 m/s.



Discussion

No Comment Found