A stone is thrown vertically upwards with a speed of 20m/s. If g = 10m

1.	A stone is thrown vertically upwards with a speed of 20m/s. If g = 10m/s2, find(1) Time is taken by the stone to reach the maximum height.(2) Total distance covered by the stone to reach the maximum height.
Answer» We are given that: Initial velocity (u) = 20 m/s When an object attain maximum height, then final velocity (ν) = 0 a = g = 10m/s², time (t) = ? (1) From first equation of motion, we have v = u – gt ⇒ 0 = 20 - 10 x t ⇒ 10t = 20 ⇒ t = 2 sec (2) From third equation of motion, we have v²= u² – 2gh ⇒ (0)² = (20)² - 2 x 10 x h ⇒ 20h = 20 x 20 ⇒ h = 20 m

A stone is thrown vertically upwards with a speed of 20m/s. If g = 10m/s2, find(1) Time is taken by the stone to reach the maximum height.(2) Total distance covered by the stone to reach the maximum height.

Answer»

We are given that: Initial velocity (u) = 20 m/s

When an object attain maximum height, then final velocity (ν) = 0

a = g = 10m/s², time (t) = ?

(1) From first equation of motion, we have v = u – gt

⇒ 0 = 20 - 10 x t

⇒ 10t = 20

⇒ t = 2 sec

(2) From third equation of motion, we have
v²= u² – 2gh

⇒ (0)² = (20)² - 2 x 10 x h

⇒ 20h = 20 x 20

⇒ h = 20 m

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A stone is thrown vertically upwards with a speed of 20m/s. If g = 10m/s2, find(1) Time is taken by the stone to reach the maximum height.(2) Total distance covered by the stone to reach the maximum height.

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