1.

A stone is thrown with a velocity v at an angle 0 with the horizontal. Its speed when it makes an angle /3 with the horizontal is :

Answer»

`vcostheta`
`v/(cosbeta)`
`vcosthetacosbeta`
`(vcostheta)/(vcosbeta)`

SOLUTION :Here the horizontal COMPONENT remains CONSTANT i.e. if U is the vel. after the angle changes from `THETA` to `beta`, then `ucosbeta=vcosthetaoru=(vcostheta)/(cosbeta)`


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