A stone lying at rest in a river The minimum mass of stone, `m = krhov^(x) g^(-3)` is needed for remaining at rest here, `h =` constant having no unit , `g =` acceleration due to gravity , `v =` river flor velocity , `rho =` density of water. The value of x isA. `3`B. `5`C. `6`D. `8`

A stone lying at rest in a river The minimum mass of stone, `m = krhov

1.	A stone lying at rest in a river The minimum mass of stone, `m = krhov^(x) g^(-3)` is needed for remaining at rest here, `h =` constant having no unit , `g =` acceleration due to gravity , `v =` river flor velocity , `rho =` density of water. The value of x isA. `3`B. `5`C. `6`D. `8`
Answer» Correct Answer - c The unit of LHS is `kg` The unit of RHS should be `kg` Here `krhov^(2)g^(-3)= ((kg)/(m^(3))) ((m)/(s))^(x)((m)/(s^(2)))^(-3)` `= (kg) (m)^(-3+x - 3)(s)^(+6-x)` `:. -6 +x = 0` `rArr x = 6`

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A stone lying at rest in a river The minimum mass of stone, `m = krhov^(x) g^(-3)` is needed for remaining at rest here, `h =` constant having no unit , `g =` acceleration due to gravity , `v =` river flor velocity , `rho =` density of water. The value of x isA. `3`B. `5`C. `6`D. `8`

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