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Unit of `(CV)/(rho epsilon_(0))` are of (`C =` capacitance, `V =` potential, `rho =` specfic resistence and `epsilon_(0) =` permittivity of free space)`A. ChargeB. currentC. timeD. frequency |
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Answer» Correct Answer - b `C = (epsilon_(0)A)/(d)` and `rho = (RA)/(l)` Substituting in `(CV)/(rhoepsilon_(0))` we get `(CV)/(rhoepsilon_(0))= (((epsilon_(0)A)/(d))(V))/((R (A)/(l)) epsilon_(0))-="current"`. |
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