1.

A stone of mass 0.005 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion ?

Answer»

0.049 N vertically downwards
9.8 N vertically downwards
0.49 N vertically UPWARDS
0.98 N vertically downwards.

Solution :When the stone is THROWN vertically upward then net force on the stone is F=mg actiing vertically downwards
`:. F=0.005xx9.8=0.49 N` vertically downwards.


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