1.

A stone of mass 0.05 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?

Answer»

9.8 N VERTICALLY DOWNWARDS
0.98N vertically downwards
0.49N vertically downwards
0.49N vertically downwards

Solution :`vec(F)_(G)= +m vec(g)= 0.05 XX (-9.8 hat(j)) = -0.49 hat(j)= 0.49N` vertically downwards


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