A stone of mass 1 kg tied at the end of a string of length 1 m and is whirled in a verticle circle at a constant speed of `3 ms^(-1)`. The tension in the string will be 19 N when the stone is `(g=10 ms^(-1))`A. at the top most point on the vertical circleB. at the bottom most point on the vertical circleC. half way downD. making an angle `30^(@)` with the vertical

A stone of mass 1 kg tied at the end of a string of length 1 m and is

1.	A stone of mass 1 kg tied at the end of a string of length 1 m and is whirled in a verticle circle at a constant speed of `3 ms^(-1)`. The tension in the string will be 19 N when the stone is `(g=10 ms^(-1))`A. at the top most point on the vertical circleB. at the bottom most point on the vertical circleC. half way downD. making an angle `30^(@)` with the vertical
Answer» Correct Answer - B `T=(mv^(2))/(r)+mg cos theta` `mg cos theta=T-(mv^(2))/(r)=19-(1xx9)/(1)=19-9` `mg cos theta =10` `therefore cos theta =(10)/(mg)=(10)/(1xx10)` `cos theta =1` `theta= cos ^(-1)(1)=0` At the bottom

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