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A stone of mass 2.0 kg is tied to the end of a string of m length. It is whirled in a horizontal circle. If the breaking tension of the string is 400 N, calculate the maximum velocity of the stone. |
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Answer» SOLUTION :`m=2.0 kg, r =2m`, TENSION = 400 N. When the tension in the STRING reaches the breaking tension, the velocity of the body becomes MAXIMUM. Let the maximum velocity be v. Tension = centripetal FORCE `400=(mv^(2))/(r ) rArr 400=(2xx v^(2))/(2)` `v^(2)=400 , v=20 ms^(-1)`. |
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