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A stone of mass 2 kg is projected upwards with KE of 98 J. The height at which the KE of the body becomes half its original value, is given by (take, `g=9.8ms^(-2)`)A. 5 mB. 2.5 mC. 1.5 mD. 0.5 m |
Answer» Correct Answer - B (b) At this height, half is PE `:. Mgh=(98)/(2)" or " 2xx9.8xxh=49" or " h=2.5 m` |
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