1.

A stone of mass 4 kg whirled in a horizontal circle of radius 1 m and makes 2 revolutions/s. Moment of inertia of the stone about the axis of rotation is :

Answer»

`65kgm^(2)`
`4kgm^(2)`
`16kgm^(2)`
`1kgm^(2)`

SOLUTION :`I=mr^(2).=4xx1^(2)=4kgm^(2)`


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