InterviewSolution
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InterviewSolution
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A stone thrown vertically upwards takes 3 seconds to attain maximum height, calculate(i) initial velocity of stone(ii) maximum height attained by the stone |
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Answer» Let, u = Initial velocity of stone H = Maximum height attained by the stone v = final velocity at maximum height = 0 t = time taken to attain maximum height = 3 s a = -g = acceleration due to gravity (i) We know that, v = u + at 0 = u – g × 3 u = 3g = 3 × 9.8 ms-2 u = 29.4 ms-1 (ii) From the equations of motion, we know that, S = ut + \(\frac{1}{2}\)at2 H = 29.4 x 3 + \(\frac{1}{2}\)9.8 x 9 H = 88.2 + 44.1 H = 132.3 m |
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