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A stone tied to a string is rotated with a uniform speed in a vertical plane. If mass of the stone is `m`, the length of the string is `r` and linear speed of the stone is `v` when the stone is at its lowest point, then the tension in the string will be (g= acceleration due to gravity)A. `(mv^(2))/r+mg`B. `(mv^(2))/r-mg`C. `(mv^(2))/r`D. `mg` |
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Answer» Correct Answer - A `T-mg=(mv^(2))/r` (centripetal force at lowest point) `T=(mv^(2))/r+mg` |
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