A stone tied to the end of the string 80cm long is whirled in a horizo – InterviewSolution

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1.	A stone tied to the end of the string 80cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolutions in 25s . what is the magnitude and direction of acceleration of the stone.
Answer» Length of string = 80CM= 0.8mStone makes 14 revolution in 25 sectherefore, Stone makes 14/25 revolution in 1 secfrequency= 14/25 sec^-1 We knowAngular SPEED (ω) = 2π×frequency=2π×14/25=28π/25 rad/secNow ACCELERATION(a) =ω²rwhere r is the radius { length of the string }Acceleration =0.8 × {28π/25}²= 9.91 m/s²Explanation:Hope this helps

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