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A stone weighs 100N on the surface of the Earth. The ratio of its weight at a height of half the radius of the Earth to a depth of half the radius of the earth will be approximately |
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Answer» 3.6 `=(R^(2))/(((3R)/(2))^(2))=(4)/(9) rArr W_(h)=100xx(4)/(9)` `(W_(d))/(W)=(g.)/(g)=1-(d)/(R )=1-(1)/(2)=(1)/(2) rArr W_(d)=100xx(1)/(2)` `therefore (W_(h))/(W_(d))=((100xx4)/(9))/(100//2)=(8)/(9)=0.9` So CORRECT choice is (d). |
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