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A storage battery of emf 8.0 V and internal resistance 0.5 Omegais being charged by a 120 Omegad.c.supply using a series resistor of 15.5 Omega . What is the terminal voltage of the battery duringcharging ? What is the purpose of having a series resistor in the charging circuit ?

Answer»

Solution :Here` EPSI = 8.0V , r = 0.5 Omega , R = 15.5 Omega` and external supply voltage `epsi_0 = 120 V`
If CHARGING current I, then during charging net effective emf `epsi_0 - epsi = I (R+ r)`
` RARR I = (epsi_0 - epsi)/(R + r) = (120 - 8.0)/( (15.5 + 0.5 ) ) = 7A`
` therefore ` Terminal voltage of the battery during charging
` V = epsi + RI = 8.0 + 0.5 xx 7 = 11.5 V`


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