1.

A storage battery of emf 8.0 V and internal resistance 0.5 Omegais being charged by a 120 V de supply using a series resistor of 15.5 Omega . What is the terminal voltage of the battery during charging ?

Answer»

Solution :Charging CURRENT is given by formula,
`I = (V - epsilon)/(R + r)`
= `(120 - 8)/(15.5 + 0.5) `
= ` (112)/(16) `
`THEREFORE ` I = 7A
Terminal voltage of battery during its charging
`V. = epsilon` + Ir
= 8 + (7) (0.5)
8 + 3.5
`therefore V. = 11.5` V
By connecting series resistance, we can reduc charging current (with the increase in chargin, time). By REDUCING charging current, we reduce the heat loss in the internal resistance.


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