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A storage capacitor on a RAM chip has a capacity 48fF. If the capacitor is charged to a potential of 4.6V, how many excess electrons are on its negative plate? |
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Answer» Solution :Data supplied, `C=48fF=48 xx 10^(-15)F` `V=4.6V` `e=1.6 xx 10^(-19)C` `q=ne and q=CV ""N=(CV)/e=(48 xx 10^(-15)xx 4.6)/(1.6 xx 10^(-19))=(48 xx 46 xx 10^(4))/(16)` `n=1.38 xx 10^(6)"ELECTRONS"` |
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