1.

A straight conductor 0.1 m long moves in a uniform magnetic field 0.1 T. The velocity of the conductor is 15 m/s and is directed perpendicular to the field. The e.m.f. induced between the two ends of the conductor is

Answer»

0.10 V
0.15 V
1.50 V
15.00 V

Solution :Assuming magnetic FIELD (B), conductor length (l) and its velocity (v) are mutually perpendicular so, EMF induced between the two ENDS of the conductor
`epsilon = Blv`
Here, `B=0.1 T, l=0.1 m, v = 15 ms^(-1), epsilon = ?`
`epsilon =0.1xx0.1xx15=0.15 V`


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