1.

A straight conductor 2m long carrying of 15 A is kept at right angles to a uniform magnetic field of induction 5xx10^(-3) (Wb)//m^2. What is the force acting upon it ?

Answer»

SOLUTION :We have `F=ilBsintheta`
Here i=15amp, l=2m,
`B=5xx10^(-3) (WB)//m^2` and `theta=90^@`
`THEREFORE F=15xx2xx5xx10^(-3)=0.15N`


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