1.

A straight conductor of length L and carrying a current I is kept in a uniform magnetic field of induction vec B. Write theexpressions for the force on the conductor and the magnitude of the maximum force.

Answer»

Solution :The force on the current- carrying conductor is
` vecF = VEC(IL) XX vecB`
where vecL is in the direction of the current.
` |vecF| = ILB sin theta`
` :. |vecF_("max")| = ILB`
when the ANGLE ` theta` between `vecL and vecB " is " 90^(@)`.


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