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A straight conductor of length L and carrying a current I is kept in a uniform magnetic field of induction vec B. Write theexpressions for the force on the conductor and the magnitude of the maximum force. |
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Answer» Solution :The force on the current- carrying conductor is ` vecF = VEC(IL) XX vecB` where vecL is in the direction of the current. ` |vecF| = ILB sin theta` ` :. |vecF_("max")| = ILB` when the ANGLE ` theta` between `vecL and vecB " is " 90^(@)`. |
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