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A straight horizontal conducing rod of lenght 0.45 m and mass 60 g is suspend by two vetical wires at its ends. A current of 5.0 A is set up in the rod through the wires. a. What magnetic field should be set up normal to the conductor in order that the tension in the wires is zero ? b. What will be the total tension in the wires if the direction of current is reversed keeping the magnetic field same as before ? (Ignore the mass of the wires.) g= 9.8 ms^(-2) |
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Answer» Solution :l= 0.5 m and mass m = 60 G , I - 5 A a. BIL = MG `therefore B= (60 xx 10^(-3) xx 9.8 xx 100)/(5 xx 0.45) = 261.6 = 0.26 I` b. `2 mg = 2 xx 60 xx 10^(-2) xx 9.8 = 117.6 = 1.176 N` |
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