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A straight line l with negative slope passes through (8,2) and cuts the coordinate axes at P and Q. Find absolute minimum value of 'OP+OQ`` where O is the origin- |
Answer» Correct Answer - 18 Let the equation of line be (y-2) = m(x-8) where `m lt 0.` `rArr P-= (8-(2)/(m), 0)" and " Q -=(0 ,2-8m)` `"Now, "OP+OQ =|8-(2)/(m)| + |2 -8m|` `= 10+(2)/(-m) + (-8m)` `ge 10+2sqrt((2)/(-m) xx(-8m)) ge 18` |
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