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A straight line through the point A(3, 4) is such that its intercept between the axes is bisected at A. Its equation is :A. `x+y=7`B. `3x-4y+7=0`C. `4x+3y=24`D. `3x+4y=25` |
Answer» Correct Answer - C Let the equation of the line be `(x)/(a)+(y)/(b)=1` . It cuts the coordinates axes at P(a,0) and Q(0,b) . It is given that PQ is bisector at A(3,4). `therefore (a+0)/(2)=3 and (0+b)/(2)=4 implies a=6,b=8`. Hence, the equation of the line is `(x)/(6)+(y)/(8)=1` or , `4x+3y=24` . |
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