1.

A straight steel wire of length l has magnetic moment m. If the wire is bent in the form of a semicircle the new value of the magnetic dipole moment is ......... .

Answer»

`m`
`(2M)/(pi)`
`(m)/(2)`
`(m)/(pi)`

Solution :Magnetic dipole MOMENT of wire of length `l`.
`m=pl` Now wire of length `l` is bent in the form of a semicircle its radius
`R= (l)/(pi)`
`THEREFORE` Distance between two ENDS of wire (new length of a magnet)
`l.= 2r`
`thereforel. = (2l)/(pi)`
New magnetic dipole moment `m. = pl. = (2pl)/(pi)`
`therefore m. = (2m)/(pi)`


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